BASH Command Query!! Organisation: Free Agent via Linux OS and Wine Emulator

I am trying to batch process a bunch of camera photo files and have a working command but I'm trying to refine it.

I have a series of photo files with the following syntax: crw1270.crw crw1271.crw

I have written a script to convert to a low res jpeg:

crw1270.crw crw1270.crw.lo.jpg crw1271.crw crw1271.crw.lo.jpg

But, I'm trying to shorten the resulting output file name a bit. I've tried the following command (watch for the line wrap):

for i in *.crw; j=`echo $i cut -d "." -f 1`; do dcraw -w -c $i

To attempt to get this result ...

crw1270.crw crw1270.lo.jpg crw1271.crw crw1271.lo.jpg

But I get this error message!

-bash: syntax error near unexpected token `j=`echo $i cut -d "." -f 1`'

Can anyone suggest a simple solution or point out what I'm doing wrong?!?! This is really just a "nice to have" but I haven't run into this problem in a shell script, only in this extended command method.

Thanks in advance! -- ------------------------------------------------ SPAM Reduction: Remove "x." from my domain. ------------------------------------------------