Printing all arguments pbutted to a bash script 2473

Well, it is not the same. To see why, test each one with an argument that contains at least one space.

Here is a test script to show the difference:

######################################################## #!-bin-bash

echo echo "Default method" Count=0 for arg do Count=$(( $Count + 1 )) echo "Parameter $Count = '$arg'" done

echo echo '"$*" method' Count=0 for arg in "$*" do Count=$(( $Count + 1 )) echo "Parameter $Count = '$arg'" done

echo Count=0 do Count=$(( $Count + 1 )) echo "Parameter $Count = '$arg'" done

echo echo '$* method' Count=0 for arg in $* do Count=$(( $Count + 1 )) echo "Parameter $Count = '$arg'" done ########################################################

$ tmp-list-args.sh a b c d e 'f g' h

Default method Parameter 1 = 'a' Parameter 2 = 'b' Parameter 3 = 'c' Parameter 4 = 'd' Parameter 5 = 'e' Parameter 6 = 'f g' Parameter 7 = 'h'

"$*" method Parameter 1 = 'a b c d e f g h'

Parameter 1 = 'a' Parameter 2 = 'b' Parameter 3 = 'c' Parameter 4 = 'd' Parameter 5 = 'e' Parameter 6 = 'f g' Parameter 7 = 'h'

$* method Parameter 1 = 'a' Parameter 2 = 'b' Parameter 3 = 'c' Parameter 4 = 'd' Parameter 5 = 'e' Parameter 6 = 'f' Parameter 7 = 'g' Parameter 8 = 'h'

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